Physics · 2021
JEE Main · 26 August 2021, Shift 2 · Q8
The de-Broglie wavelength of a particle having kinetic energy E is λ. How much extra energy must be given to this particle so that the de-Broglie…
The de-Broglie wavelength of a particle having kinetic energy E is $\displaystyle \lambda$. How much extra energy must be given to this particle so that the de-Broglie wavelength reduces to $\displaystyle 75$% of the initial value ?
Official answer
(3)
$\displaystyle \frac{7}{9} \mathrm{E}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.