Physics · 2024
JEE Main · 27 January 2024, Shift 1 · Q39
The average kinetic energy of a monoatomic molecule is 0.414 eV at temperature: (Use K_B =1.38 × 10^-23 J / mol - K )
The average kinetic energy of a monoatomic molecule is $\displaystyle 0.414$ eV at temperature :
(Use $\displaystyle \mathrm{K}_{\mathrm{B}}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ )
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 3200$ K
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.