Physics · 2022
JEE Main · 24 June 2022, Shift 2 · Q41
Potential energy as a function of r is given by U=A/(r^10)-B/r^5, where r is the interatomic distance, A and B are positive constants. The…
Potential energy as a function of $\displaystyle r$ is given by $\displaystyle U=\frac{A}{r^{10}}-\frac{B}{r^5}$, where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be :
Official answer
(3)
$\displaystyle \left(\frac{2 A}{B}\right)^{\frac{1}{5}}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.