Physics · 2023
JEE Main · 1 February 2023, Shift 2 · Q23
Moment of inertia of a disc of mass M and radius ' R ' about any of its diameter is (M R^2)/4. The moment of inertia of this disc about an axis…
Moment of inertia of a disc of mass $\displaystyle M$ and radius ' $\displaystyle R$ ' about any of its diameter is $\displaystyle \frac{\mathbf{M R}^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\displaystyle \frac{x}{2} \mathrm{MR}^2$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
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From NTA’s final answer key for this paper.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.