Physics · 2019
JEE Main · 9 April 2019, Shift 2 · Q6
Moment of inertia of a body about a given axis is 1.5 kg m^2. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200…
Moment of inertia of a body about a given axis is $\displaystyle 1.5 \mathrm{~kg} \mathrm{~m}^2$. Initially the body is at rest. In order to produce a rotational kinetic energy of $\displaystyle 1200$ J, the angular acceleration of $\displaystyle 20 \mathrm{rad} / \mathrm{s}^2$ must be applied about the axis for a duration of :
Official answer
(3)
$\displaystyle 2$ s
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.