Moment of Inertia (M.I.) of four bodies having same mass ' M ' and radius ' 2 R ' are as follows: I_1= M.I. of solid sphere about its diameter I_2=…

Moment of Inertia (M.I.) of four bodies having same mass ' $\displaystyle M$ ' and radius ' $\displaystyle 2 R$ ' are as follows : $\displaystyle \mathrm{I}_1=$ M.I. of solid sphere about its diameter $\displaystyle \mathrm{I}_2=$ M.I. of solid cylinder about its axis $\displaystyle \mathrm{I}_3=$ M.I. of solid circular disc about its diameter $\displaystyle \mathrm{I}_4=$ M.I. of thin circular ring about its diameter If $\displaystyle 2\left(\mathrm{I}_2+\mathrm{I}_3\right)+\mathrm{I}_4=x \cdot \mathrm{I}_1$ then the value of $\displaystyle x$ will be \_\_\_\_.