Physics · 2024
JEE Main · 6 April 2024, Shift 2 · Q35
Match List-I with List-II: Choose the correct answer from the options given below:
Match List-I with List-II :
Choose the correct answer from the options given below :
| List-I | List-II | ||
| Y vs X | Shape of Graph | ||
| (A) | $\displaystyle \mathrm{Y}=$ magnetic susceptibility X = magnetising field | (I) |  |
| (B) | $\displaystyle \mathrm{Y}=$ magnetic field X=distance from centre of a current carrying wire for $\displaystyle x<\mathrm{a}$ (where $\displaystyle \mathrm{a}=$ radius of wire) | (II) |  |
| (C) | $\displaystyle Y=$ magnetic field X=distance from centre of a current carrying wire for $\displaystyle x>\mathrm{a}$ (where $\displaystyle \mathrm{a}=$ radius of wire) | (III) |  |
| (D) | $\displaystyle \mathrm{Y}=$ magnetic field inside solenoid X = distance from centre | (IV) |  |
Official answer
(2)
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.