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Physics · 2026

JEE Main · 6 April 2026, Shift 2 · Q45

In a Young double slit experiment, the wavelength of incident light is 6000, the separation between slits S_1 and S_2 is 5 cm and the distance…

In a Young double slit experiment, the wavelength of incident light is $\displaystyle 6000 \AA$, the separation between slits $\displaystyle S_1$ and $\displaystyle S_2$ is $\displaystyle 5$ cm and the distance between slits plane and screen is $\displaystyle 50$ cm, as shown in the figure below. If the resultant intensity at $\displaystyle P$ is equal to the intensity due to individual slits, the path difference between interfering waves is $\displaystyle \_\_\_\_$ Å. Figure: JEE Main Physics 2026, Wave Optics
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.