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Physics · 2026

JEE Main · 2 April 2026, Shift 1 · Q46

In single slit diffraction pattern, the wavelength of light used is 628 nm and slit width is 0.2 mm, the angular width of central maximum is α ×…

In single slit diffraction pattern, the wavelength of light used is $\displaystyle 628$ nm and slit width is $\displaystyle 0.2$ mm, the angular width of central maximum is $\displaystyle \alpha \times 10^{-2}$ degrees. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
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