Physics · 2013
JEE Main · 22 April 2013, Shift 1 · Q15
In a series L-C-R circuit, C =10^-11 Farad, L =10^-5 Henry and R =100 Ohm, when a constant D.C voltage E is applied to the circuit, the capacitor…
In a series L-C-R circuit, $\displaystyle \mathrm{C}=10^{-11}$ Farad, $\displaystyle \mathrm{L}=10^{-5}$ Henry and $\displaystyle \mathrm{R}=100 \mathrm{Ohm}$, when a constant D.C voltage E is applied to the circuit, the capacitor acquires a charge $\displaystyle 10^{-9} \mathrm{C}$. The D.C. source is replaced by a sinusoidal voltage source in which the peak voltage $\displaystyle \mathrm{E}_0$ is equal to the constant D.C. voltage E. At resonance the peak value of the charge acquired by the capacitor will be :
Official answer
(4)
$\displaystyle 10^{-8} \mathrm{C}$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.