Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q2
In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ' v ' more than that of…
In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ' $\displaystyle v$ ' more than that of car B. Both the cars start from rest and travel with constant acceleration $\displaystyle \mathrm{a}_1$ and $\displaystyle \mathrm{a}_2$ respectively. Then ' $\displaystyle v$ ' is equal to :
Official answer
(2)
$\displaystyle \sqrt{a_1 a_2} t$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.