Physics · 2021
JEE Main · 27 August 2021, Shift 1 · Q23
If the velocity of a body related to displacement x is given by v=√(5000+24 x) m / s, then the acceleration of the body is \ \ \ \ m / s^2.
If the velocity of a body related to displacement $\displaystyle x$ is given by $\displaystyle v=\sqrt{5000+24 x} \mathrm{~m} / \mathrm{s}$, then the acceleration of the body is \_\_\_\_ $\displaystyle \mathrm{m} / \mathrm{s}^{2}$.
Official answer
12
More from Motion in One Dimension
- A body is moving with constant speed, in a circle of radius 10 m. The body completes one revolution in 4 s. At the end of 3rd second, the…2023
- Given below are two statements: Statement I: Area under velocity- time graph gives the distance travelled by the body in a given time. Statement II:…2023
- A body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1. If it is projected vertically downwards…2024
- A particle moves in a straight line so that its displacement x at any time t is given by x^2=1+t^2. Its acceleration at any time t is x^-n where n=…2024
- A body starts moving from rest with constant acceleration covers displacement S_1 in first (p-1) seconds and S_2 in first p seconds. The displacement…2024
- A train starting from rest first accelerates uniformly up to a speed of 80 km / h for time t, then it moves with a constant speed for time 3 t. The…2024
- The motion of an airplane is represented by velocity-time graph as shown below. The distance covered by airplane in the first 30.5 second is ____ km.2025
- From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same…2022
JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.