Physics · 2019
JEE Main · 8 April 2019, Shift 1 · Q11
If 10^22 gas molecules each of mass 10^-26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m^2 with a speed…
If $\displaystyle 10^{22}$ gas molecules each of mass $\displaystyle 10^{-26} \mathrm{~kg}$ collide with a surface (perpendicular to it) elastically per second over an area $\displaystyle 1 \mathrm{~m}^2$ with a speed $\displaystyle 10^4 \mathrm{~m} / \mathrm{s}$, the pressure exerted by the gas molecules will be of the order of :
Official answer
(1)
$\displaystyle 10^3 \mathrm{~N} / \mathrm{m}^2$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.