Physics · 2021
JEE Main · 3 August 2021, Shift 1 · Q12
Consider the case of a non-homogeneous solid cylinder of radius R carrying a current ' I ' such that the current density depends on the radial…
Consider the case of a non-homogeneous solid cylinder of radius R carrying a current ' $\displaystyle I$ ' such that the current density depends on the radial distance ' $\displaystyle r$ ' from the axis of the cylinder as $\displaystyle \mathrm{J}=\sigma r$, ( $\displaystyle \sigma$ is constant). The magnetic field at a point 'P' at a perpendicular distance $\displaystyle r(<\mathrm{R})$ from the axis of the cylinder is -
Official answer
(2)
$\displaystyle \frac{\mu_0 \mathrm{I} r^2}{2 \pi \mathrm{R}^3}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.