Physics · 2021
JEE Main · 4 August 2021, Shift 1 · Q28
A potential difference of 800 V is applied across the plates of a parallel plate capacitor. The separation between the plates is 5 mm and a uniform…
A potential difference of $\displaystyle 800$ V is applied across the plates of a parallel plate capacitor. The separation between the plates is $\displaystyle 5$ mm and a uniform magnetic field is applied parallel to the plates horizontally. An electron projected vertically parallel to the plates, with a velocity of $\displaystyle 2 \times 10^6 \mathrm{~m} / \mathrm{s}$ moves undeflected between the plates. The magnitude of the magnetic field will be \_\_\_\_$\displaystyle \times 10^{-2} \mathrm{~T}$.
Official answer
8
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.