Physics · 2023
JEE Main · 30 January 2023, Shift 1 · Q5
As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest.…
As per the given figure, a small ball $\displaystyle P$ slides down the quadrant of a circle and hits the other ball $\displaystyle Q$ of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be :
$$\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
$$
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 2 \mathrm{~m} / \mathrm{s}$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.