Physics · 2025
JEE Main · 24 January 2025, Shift 1 · Q27
An object of mass ' m ' is projected from origin in a vertical xy plane at an angle 45^° with the x - axis with an initial velocity v_0. The…
An object of mass ' m ' is projected from origin in a vertical xy plane at an angle $\displaystyle 45^{\circ}$ with the x - axis with an initial velocity $\displaystyle \mathrm{v}_0$. The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ $\displaystyle g$ is acceleration due to gravity]
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{m v_o{ }^3}{4 \sqrt{2} g}$ along negative z-axis
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.