An electron (mass m ) with initial velocity v =v_0 i +v_0 j is in an electric field E =- E_0 k. If λ_0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by:

(2) (λ_0)/(√(1+(e^2 E^2 t^2)/(2 m^2 v_0^2)))

An electron (mass m ) with initial velocity v=v_0 i+v_0 j is in an electric field E=-E_0…

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Physics · 2020

Dual Nature of Matter and Radiation de Broglie Wavelength

JEE Main · 8 January 2020, Shift 2 · Q18

An electron (mass m ) with initial velocity $\displaystyle \vec{v}=v_0 \hat{i}+v_0 \hat{j}$ is in an electric field $\displaystyle \overrightarrow{\mathrm{E}}=-\mathrm{E}_0 \hat{k}$. If $\displaystyle \lambda_0$ is initial de-Broglie wavelength of electron, its de-Broglie wave length at time $\displaystyle t$ is given by :

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An electron (mass m ) with initial velocity v =v_0 i +v_0 j is in an electric field E =- E_0 k. If λ_0 is initial de-Broglie wavelength of electron,…

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