Physics · 2024
JEE Main · 30 January 2024, Shift 2 · Q43
An alternating voltage V(t)=220 sin 100 π t volt is applied to a purely resistive load of 50 Ω. The time taken for the current to rise from half of…
An alternating voltage $\displaystyle V(t)=220 \sin 100 \pi t$ volt is applied to a purely resistive load of $\displaystyle 50 \Omega$. The time taken for the current to rise from half of the peak value to the peak value is:
Official answer
From NTA’s final answer key for this paper.
(1)
3.$\displaystyle 3$ ms
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.