Physics · 2024
JEE Main · 31 January 2024, Shift 2 · Q43
An AC voltage V=20 sin 200 π t is applied to a series LCR circuit which drives a current I=10 sin (200 π t+(π)/3). The average power dissipated is:
An AC voltage $\displaystyle V=20 \sin 200 \pi t$ is applied to a series LCR circuit which drives a current $\displaystyle I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right)$. The average power dissipated is:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 50$ W
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