Physics · 2025
JEE Main · 24 January 2025, Shift 1 · Q36
An alternating current is given by I=I_A sin ω t+I_B cos ω t. The r.m.s current will be
An alternating current is given by $\displaystyle I=I_A \sin \omega t+I_B \cos \omega t$. The r.m.s current will be
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \sqrt{\frac{\mathrm{I}_{\mathrm{A}}^2+\mathrm{I}_{\mathrm{B}}^2}{2}}$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.