Physics · 2025
JEE Main · 3 April 2025, Shift 2 · Q37
An electric bulb rated as 100 W -220 V is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is:
An electric bulb rated as $\displaystyle 100 \mathrm{~W}-220 \mathrm{~V}$ is connected to an ac source of rms voltage $\displaystyle 220$ V . The peak value of current through the bulb is :
Official answer
From NTA’s final answer key for this paper.
(3)
0.$\displaystyle 64$ A
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.