Physics · 2020
JEE Main · 9 January 2020, Shift 2 · Q3
A uniformly thick wheel with moment of inertia I and radius R is free to rotate about its centre of mass (see fig). A massless string is wrapped over…
A uniformly thick wheel with moment of inertia I and radius R is free to rotate about its centre of mass (see fig). A massless string is wrapped over its rim and two blocks of masses $\displaystyle \mathrm{m}_1$ and $\displaystyle \mathrm{m}_2\left(\mathrm{~m}_1>\mathrm{m}_2\right)$ are attached to the ends of the string. The system is released from rest. The angular speed of the wheel when $\displaystyle \mathrm{m}_1$ descents by a distance $\displaystyle h$ is :
Official answer
(2)
$\displaystyle \left[\frac{2\left(m_1-m_2\right) g h}{\left(m_1+m_2\right) R^2+I}\right]^{\frac{1}{2}}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.