Physics · 2019
JEE Main · 9 April 2019, Shift 1 · Q5
A uniform cable of mass ' M ' and length ' L ' is placed on a horizontal surface such that its (1/n)^th part is hanging below the edge of the…
A uniform cable of mass ' M ' and length ' L ' is placed on a horizontal surface such that its $\displaystyle \left(\frac{1}{\mathrm{n}}\right)^{\text {th }}$ part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :
Official answer
(3)
$\displaystyle \frac{\mathrm{MgL}}{2 \mathrm{n}^2}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.