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Physics · 2025

JEE Main · 24 January 2025, Shift 1 · Q50

A square loop of sides a=1 m is held normally in front of a point charge q =1 C. The flux of the electric field through the shaded region is 5/p ×…

A square loop of sides $\displaystyle a=1 \mathrm{~m}$ is held normally in front of a point charge $\displaystyle \mathrm{q}=1 \mathrm{C}$. The flux of the electric field through the shaded region is $\displaystyle \frac{5}{\mathrm{p}} \times \frac{1}{\varepsilon_0} \frac{\mathrm{Nm}^2}{\mathrm{C}}$, where the value of p is $\displaystyle \_\_\_\_$. Figure: JEE Main Physics 2025, Electrostatics
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.