Physics · 2019
JEE Main · 12 April 2019, Shift 2 · Q6
A smooth wire of length 2 π r is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating…
A smooth wire of length $\displaystyle 2 \pi \mathrm{r}$ is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed $\displaystyle \omega$ about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of $\displaystyle \omega^2$ is equal to :
Official answer
(4)
$\displaystyle 2 g /(r \sqrt{3})$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.