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Physics · 2020
JEE Main · 8 January 2020, Shift 1 · Q2
A particle of mass m is fixed to one end of a light spring having force constant k and unstretched length l. The other end is fixed. The system is…
A particle of mass $\displaystyle m$ is fixed to one end of a light spring having force constant k and unstretched length $\displaystyle l$. The other end is fixed. The system is given an angular speed $\displaystyle \omega$ about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is :
Official answer
(2)
$\displaystyle \frac{\mathrm{ml} \omega^2}{\mathrm{k}-\mathrm{m} \omega^2}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.