Physics · 2014
JEE Main · 12 April 2014, Shift 1 · Q21
A sinusoidal voltage V ( t )=100 sin (500 t ) is applied across a pure inductance of L =0.02 H. The current through the coil is:
A sinusoidal voltage $\displaystyle \mathrm{V}(\mathrm{t})=100 \sin (500 \mathrm{t})$ is applied across a pure inductance of $\displaystyle \mathrm{L}=0.02 \mathrm{H}$. The current through the coil is :
Official answer
(2)
$\displaystyle -10 \cos (500 \mathrm{t})$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.