Physics · 2021
JEE Main · 26 February 2021, Shift 2 · Q12
A scooter accelerates from rest for time t_1 at constant rate a_1 and then retards at constant rate a_2 for time t_2 and comes to rest. The correct…
A scooter accelerates from rest for time $\displaystyle t_1$ at constant rate $\displaystyle a_1$ and then retards at constant rate $\displaystyle \mathrm{a}_2$ for time $\displaystyle \mathrm{t}_2$ and comes to rest. The correct value of $\displaystyle \frac{\mathrm{t}_1}{\mathrm{t}_2}$ will be :
Official answer
(2)
$\displaystyle \frac{\mathrm{a}_2}{\mathrm{a}_1}$
More from Motion in One Dimension
- A body is moving with constant speed, in a circle of radius 10 m. The body completes one revolution in 4 s. At the end of 3rd second, the…2023
- Given below are two statements: Statement I: Area under velocity- time graph gives the distance travelled by the body in a given time. Statement II:…2023
- A body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1. If it is projected vertically downwards…2024
- A particle moves in a straight line so that its displacement x at any time t is given by x^2=1+t^2. Its acceleration at any time t is x^-n where n=…2024
- A body starts moving from rest with constant acceleration covers displacement S_1 in first (p-1) seconds and S_2 in first p seconds. The displacement…2024
- A train starting from rest first accelerates uniformly up to a speed of 80 km / h for time t, then it moves with a constant speed for time 3 t. The…2024
- The motion of an airplane is represented by velocity-time graph as shown below. The distance covered by airplane in the first 30.5 second is ____ km.2025
- From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same…2022
JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.