Physics · 2013
JEE Main · 25 April 2013, Shift 1 · Q27
A ring of mass M and radius R is rotating about its axis with angular velocity ω. Two identical bodies each of mass m are now gently attached at the…
A ring of mass M and radius R is rotating about its axis with angular velocity $\displaystyle \omega$. Two identical bodies each of mass m are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be :
Official answer
(3)
$\displaystyle \frac{\mathrm{Mm}}{(\mathrm{M}+2 \mathrm{~m})} \omega^2 \mathrm{R}^2$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.