Physics · 2018
JEE Main · 16 April 2018, Shift 1 · Q21
A plane electromagnetic wave of wavelength λ has an intensity I. It is propagating along the positive Y-direction. The allowed expressions for the…
A plane electromagnetic wave of wavelength $\displaystyle \lambda$ has an intensity I. It is propagating along the positive Y-direction. The allowed expressions for the electric and magnetic fields are given by :
Official answer
(1)
$$\begin{aligned}
& \overrightarrow{\mathrm{E}}=\sqrt{\frac{2 \mathrm{I}}{\epsilon_{\mathrm{o}} \mathrm{c}}} \cos \left[\frac{2 \pi}{\lambda}(y-\mathrm{ct})\right] \hat{k} ; \\
& \overrightarrow{\mathrm{B}}=+\frac{1}{\mathrm{c}} \mathrm{E} \hat{i}
\end{aligned}
$$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.