Physics · 2021
JEE Main · 27 July 2021, Shift 2 · Q3
A particle of mass M originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation…
A particle of mass M originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation
$$\mathrm{F}=\mathrm{F}_0\left[1-\left(\frac{t-\mathrm{T}}{\mathrm{~T}}\right)^2\right]
$$
Where $\displaystyle \mathrm{F}_0$ and T are constants. The force acts only for the time interval 2T. The velocity $\displaystyle v$ of the particle after time 2T is :
Official answer
(2)
$\displaystyle 4 \mathrm{~F}_0 \mathrm{~T} / 3 \mathrm{M}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.