Physics · 2021
JEE Main · 25 July 2021, Shift 1 · Q25
A particle of mass ' m ' is moving in time ' t ' on a trajectory given by r =10 α t^2 i +5 β(t-5) j Where α and β are dimensional constants. The…
A particle of mass ' $\displaystyle m$ ' is moving in time ' $\displaystyle t$ ' on a trajectory given by
$$\vec{r}=10 \alpha t^2 \hat{i}+5 \beta(t-5) \hat{j}
$$
Where $\displaystyle \alpha$ and $\displaystyle \beta$ are dimensional constants.
The angular momentum of the particle becomes the same as it was for $\displaystyle t=0$ at time $\displaystyle t=$ \_\_\_\_ seconds.
Official answer
10
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.