Physics · 2019
JEE Main · 11 January 2019, Shift 2 · Q4
A particle of mass m is moving in a straight line with momentum p. Starting at time t =0, a force F =k t acts in the same direction on the moving…
A particle of mass $\displaystyle m$ is moving in a straight line with momentum p. Starting at time $\displaystyle \mathrm{t}=0$, a force $\displaystyle \mathrm{F}=k \mathrm{t}$ acts in the same direction on the moving particle during time interval T so that its momentum changes from p to $\displaystyle 3$ p . Here $\displaystyle k$ is a constant. The value of T is :
Official answer
(2)
$\displaystyle 2 \sqrt{\frac{\mathrm{p}}{k}}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.