Physics · 2019
JEE Main · 10 April 2019, Shift 1 · Q3
A particle of mass m is moving along a trajectory given by x=x_0+ a cos ω_1 t; y=y_0+ b sin ω_2 t The torque, acting on the particle about the…
A particle of mass $\displaystyle m$ is moving along a trajectory given by
$$\begin{aligned}
& x=x_0+\mathrm{a} \cos \omega_1 \mathrm{t} \\
& y=y_0+\mathrm{b} \sin \omega_2 \mathrm{t}
\end{aligned}
$$
The torque, acting on the particle about the origin, at $\displaystyle \mathrm{t}=0$ is :
Official answer
(1)
$\displaystyle +\mathrm{m} y_0 \mathrm{a} \omega_1^2 \hat{k}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.