Physics · 2021
JEE Main · 24 February 2021, Shift 2 · Q2
A particle is projected with velocity v_0 along x -axis. A damping force is acting on the particle which is proportional to the square of the…
A particle is projected with velocity $\displaystyle v_0$ along $\displaystyle x$-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. $\displaystyle m a=-\alpha x^2$. The distance at which the particle stops :
Official answer
(3)
$\displaystyle \left(\frac{3 v_0^2}{2 \alpha}\right)^{\frac{1}{3}}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.