Physics · 2014
JEE Main · 12 April 2014, Shift 1 · Q6
A particle is moving in a circular path of radius a, with a constant velocity v as shown in the figure. The center of circle is marked by 'C'. The…
A particle is moving in a circular path of radius a, with a constant velocity $\displaystyle v$ as shown in the figure. The center of circle is marked by 'C'. The angular momentum from the origin O can be written as :
Official answer
(1)
$\displaystyle v \mathrm{a}(1+\cos 2 \theta)$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.