Physics · 2019
JEE Main · 9 April 2019, Shift 2 · Q25
A particle ^′ P^′ is formed due to a completely inelastic collision of particles ' x ' and ' y ' having de-Broglie wavelengths ' λ_x ' and ' λ_y '…
A particle $\displaystyle { }^{\prime} \mathrm{P}^{\prime}$ is formed due to a completely inelastic collision of particles ' $\displaystyle x$ ' and ' $\displaystyle y$ ' having de-Broglie wavelengths ' $\displaystyle \lambda_x$ ' and ' $\displaystyle \lambda_y$ ' respectively. If $\displaystyle x$ and $\displaystyle y$ were moving in opposite directions, then the de-Broglie wavelength of 'P' is :
Official answer
(3)
$\displaystyle \frac{\lambda_x \lambda_y}{\left|\lambda_x-\lambda_y\right|}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.