Physics · 2023
JEE Main · 11 April 2023, Shift 1 · Q41
A parallel plate capacitor of capacitance 2 F is charged to a potential V, The energy stored in the capacitor is E_1. The capacitor is now connected…
A parallel plate capacitor of capacitance $\displaystyle 2$ F is charged to a potential V, The energy stored in the capacitor is $\displaystyle \mathrm{E}_1$. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is $\displaystyle \mathrm{E}_2$. The ratio $\displaystyle \mathrm{E}_2 / \mathrm{E}_1$ is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 1$ : $\displaystyle 2$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.