Physics · 2018
JEE Main · 15 April 2018, Shift 1 · Q21
A monochromatic beam of light has a frequency ν=3/(2 π) × 10^12 Hz and is propagating along the direction (i + j)/(√ 2). It is polarized along the k…
A monochromatic beam of light has a frequency $\displaystyle \nu=\frac{3}{2 \pi} \times 10^{12} \mathrm{~Hz}$ and is propagating along the direction $\displaystyle \frac{\hat{i}+\hat{j}}{\sqrt{2}}$. It is polarized along the $\displaystyle \hat{k}$ direction. The acceptable form for the magnetic field is :
Official answer
(1)
$\displaystyle \begin{aligned}
& \frac{\mathrm{E}_{\mathrm{o}}}{\mathrm{C}} \frac{(\hat{i}-\hat{j})}{\sqrt{2}} \\
& \cos \left[10^4 \frac{(\hat{i}+\hat{j})}{\sqrt{2}} \cdot \overrightarrow{\mathrm{r}}-\left(3 \times 10^{12}\right) \mathrm{t}\right]
\end{aligned}$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.