Physics · 2019
JEE Main · 10 January 2019, Shift 2 · Q25
A metal plate of area 1 × 10^-4 m^2 is illuminated by a radiation of intensity 16 mW / m^2. The work function of the metal is 5 eV. The energy of the…
A metal plate of area $\displaystyle 1 \times 10^{-4} \mathrm{~m}^2$ is illuminated by a radiation of intensity $\displaystyle 16 \mathrm{~mW} / \mathrm{m}^2$. The work function of the metal is $\displaystyle 5$ eV. The energy of the incident photons is $\displaystyle 10$ eV and only $\displaystyle 10$% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be : $\displaystyle \left[1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\right]$
Official answer
(2)
$\displaystyle 10^{11}$ and $\displaystyle 5$ eV
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.