A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal…

A mass of $\displaystyle 10$ kg is suspended vertically by a rope of length $\displaystyle 5$ m from the roof. A force of $\displaystyle 30$ N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is $\displaystyle \theta=\tan ^{-1}\left(x \times 10^{-1}\right)$. The value of $\displaystyle x$ is \_\_\_\_, (Given, $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )