Physics · 2023
JEE Main · 31 January 2023, Shift 1 · Q23
A lift of mass M=500 kg is descending with speed of 2 ms^-1. Its supporting cable begins to slip thus allowing it to fall with a constant…
A lift of mass $\displaystyle M=500 \mathrm{~kg}$ is descending with speed of $\displaystyle 2 \mathrm{~ms}^{-1}$. Its supporting cable begins to slip thus allowing it to fall with a constant acceleration of $\displaystyle 2 \mathrm{~ms}^{-2}$. The kinetic energy of the lift at the end of fall through to a distance of $\displaystyle 6$ m will be
$\displaystyle \_\_\_\_$ kJ.
Official answer
From NTA’s final answer key for this paper.
7
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.