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Physics · 2018
JEE Main 2018 · 2018-04-08 Offline · Q13
A granite rod of 60 cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is 2.7 × 10^3 kg / m^3…
A granite rod of $\displaystyle 60$ cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is $\displaystyle 2.7 \times 10^3 \mathrm{~kg} / \mathrm{m}^3$ and its Young's modulus is $\displaystyle 9.27 \times 10^{10} \mathrm{~Pa}$. What will be the fundamental frequency of the longitudinal vibrations ?
Official answer
(1)
$\displaystyle 5$ kHz
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.