Physics · 2014
JEE Main · 19 April 2014, Shift 1 · Q13
A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to 0°C. If it were to go up straight without colliding with any…
A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to $\displaystyle 0$°C. If it were to go up straight without colliding with any other molecules, how high it would rise ? Assume that the height attained is much less than radius of the earth. ( $\displaystyle \mathrm{k}_{\mathrm{B}}$ is Boltzmann constant)
Official answer
(4)
$\displaystyle \frac{819 \mathrm{k}_{\mathrm{B}}}{2 \mathrm{Mg}}$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.