Physics · 2022
JEE Main · 25 June 2022, Shift 1 · Q60
A force on an object of mass 100 g is (10 i +5 j ) N. The position of that object at t =2 s is ( a i + b j ) m after starting from rest. The value of…
A force on an object of mass $\displaystyle 100$ g is $\displaystyle (10 \hat{i}+5 \hat{j}) \mathrm{N}$. The position of that object at $\displaystyle \mathrm{t}=2 \mathrm{~s}$ is $\displaystyle (\mathrm{a} \hat{i}+\mathrm{b} \hat{j}) \mathrm{m}$ after starting from rest. The value of $\displaystyle \frac{\mathrm{a}}{\mathrm{b}}$ will be \_\_\_\_.
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.