Physics · 2023
JEE Main · 1 February 2023, Shift 2 · Q22
A force F =(5+3 y^2) acts on a particle in the y -direction, where F is in newton and y is in meter. The work done by the force during a displacement…
A force $\displaystyle \mathrm{F}=\left(5+3 y^2\right)$ acts on a particle in the $\displaystyle y$-direction, where F is in newton and $\displaystyle y$ is in meter. The work done by the force during a displacement from $\displaystyle y=2 \mathrm{~m}$ to $\displaystyle y=5 \mathrm{~m}$ is $\displaystyle \_\_\_\_$J.
Official answer
From NTA’s final answer key for this paper.
132
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.