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Physics · 2020

JEE Main · 5 September 2020, Shift 1 · Q22

A force F =( i +2 j +3 k ) N acts at a point (4 i +3 j - k ) m. Then the magnitude of torque about the point ( i +2 j + k ) m will be √ x N - m. The…

A force $\displaystyle \vec{F}=(\hat{i}+2 \hat{j}+3 \hat{k}) \mathrm{N}$ acts at a point $\displaystyle (4 \hat{i}+3 \hat{j}-\hat{k}) \mathrm{m}$. Then the magnitude of torque about the point $\displaystyle (\hat{i}+2 \hat{j}+\hat{k}) \mathrm{m}$ will be $\displaystyle \sqrt{x} \mathrm{~N}-\mathrm{m}$. The value of $\displaystyle x$ is \_\_\_\_.
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