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Physics · 2018

JEE Main · 15 April 2018, Shift 2 · Q5

A disc rotates about its axis of symmetry in a horizontal plane at a steady rate of 3.5 revolutions per second. A coin placed at a distance of 1.25…

A disc rotates about its axis of symmetry in a horizontal plane at a steady rate of $\displaystyle 3.5$ revolutions per second. A coin placed at a distance of $\displaystyle 1.25$ cm from the axis of rotation remains at rest on the disc. The coefficient of friction between the coin and the disc is : $\displaystyle \left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.