Physics · 2020
JEE Main · 3 September 2020, Shift 2 · Q7
A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixure…
A calorimeter of water equivalent $\displaystyle 20$ g contains $\displaystyle 180$ g of water at $\displaystyle 25$°C. 'm' grams of steam at $\displaystyle 100$°C is mixed in it till the temperature of the mixure is $\displaystyle 31^{\circ} \mathrm{C}$. The value of ' m ' is close to (Latent heat of water $\displaystyle =540 \mathrm{cal} \mathrm{g}^{-1}$, specific heat of water $\displaystyle =1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ )
Official answer
(1)
$\displaystyle 2$
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